Recent content by hemalpansuriya

Ok. Thank you

So, Ez is zero at the contre ( because x and y = 0 ). Right ?

Please checkout solution that I have tried, B = B0cos(wt) î + B0sin(wt) ĵ ∇ x E= -∂B/∂t, -∂B/∂t = B0wt sin(wt) î - B0wtcos(wt) ĵ (∂Ez/∂y - ∂Ey/∂z) î - (∂Ez/∂x - ∂Ex/∂z) ĵ +(∂Ey/∂x - ∂Ex/∂y) k̂ = B0wt sin(wt) î - B0wtcos(wt) ĵ (∂Ez/∂y - ∂Ey/∂z) = B0wt sin(wt) ………… (1), (∂Ez/∂x -...

Many thanks for your effort.

We can apply equation, curl E = -dB/dt to find electric field generated at the centre due to rotating magnet facing its one of pole at the centre. The question is not for homework, its my personal curiosity.

Charge will experience a rotating magnetic field around it. What will be electric field ( If any ) at the centre, generated by rotation of magnet ?

Any arbitrary large value of charge B does not increase the energy radiated by charge A. But , having larger value of charge B will produce large amount of oscillating energy. So, we can not have equal amount of energy transfer here. Moreover, radiated energy from charge A does not even reach to...

According to this author, interactions are instantaneous, which we know it can not be true. As light also have finite speed, Coulomb interactions can not be instantaneous. The only way is, energy is not conserved.

Yes, I have also gone through it. But I am not convinced with author's solution. I believe that for this problem classically energy can not be conserved. I don't have any further quantum mechanical explanation.

Oscillation energy produced at charge B is also depends on magnitude of charge B. Because more charge, more force and hence more oscillating amplitude of charge B. We can take as much large magnitude of charge B as we want. This does not affect radiation energy at charge A, but it will increase...

Consider two charges A and B separated at distance D. charge B is attached on spring and can move towards and away from charge A. Now charge A is brought closer to charge B and then it is taken back to its original position. Work done in this process is zero because of conservative forces. If...

I know general proof. But I am wondering if there is no reaction force ( Lenz force ) on the magnet, what will conserve energy in this case.

Magnet can move towards charge. But it is constrained not to leave surface of platform. You can think of a track on which magnet moves towards charge.

As magnet moves, charge experiences change in magnetic field. So, there is an electric field produced in peripheral direction of tube. If charge is happened to be slightly a side to the center of tube, then it will experience a force. Since charge is attached and tube also constrained to move...

In my setup, magnet's north or south pole ( whatever you can choose ) is moving towards charge.