Recent content by hemant singh

Thanks a lot sir.. doubt cleared.

I know that u v s are state properties. But in open flow system KE PE both are present if that is taken into consideration then tds=dE+pdv? where E is total macroscopic and microscopic energy? Why do we use tds= du+ pdv ?

I have been having this doubt for long. As by the first law dq=du+dw (neglecting KE and PE change). And we know that the work done by the system can be utilized in things (eg. boundary work, shaft work, shear work, paddle wheel work..etc). For open flow system replacing dq=tds, we get, tds=du+...