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Force Per Length and Magnitude of a Current
Figured out my problem, I was using the wrong equation. F/L = u0*I1*I2/(2*pi*r) Solving gives: I = (F/L)*2*pi*r/(u0*I1) I = 87.5A Hope I didn't waste anyone's time and hopefully someone can learn from my mistakes!- hexus0
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- Forum: Introductory Physics Homework Help
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Force Per Length and Magnitude of a Current
Homework Statement 1.A long, thick (cylindrical, solid) wire of radius 3 mm carries a total current of I1 = 100A that is uniformly distributed over its cross-sectional area. The current is in the +z direction. A second, thin wire runs parallel to the axis of the thick wire and is located at a...- hexus0
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- Current Force Length Magnitude Per
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- Forum: Introductory Physics Homework Help