Recent content by Hey there

Oh my god. This is incredibly simple. I over complicated it I guess. So I have C=\dfrac{3\pi a^2}{2} 2\pi ax- \dfrac{\pi x^2}{2}=-kx+\dfrac{3 \pi a^2}{2} x=0 when t=T kT=\dfrac{3 \pi a^2}{2} k=\dfrac{3 \pi a^2}{2T} Got it.

I simplified it wrong then. I'll have another look.

I got C=2a^2(\pi-\frac{1}{4}) So 2 \pi ax-\frac{\pi x^2}{2}=-kt+2a^2(\pi -\frac{1}{4}) when x=0 t=T kT=2a^2(\pi-\frac{1}{4}) k=\dfrac{2a^2(\pi-\frac{1}{4})}{T} k=\dfrac{2a^2 \pi-\frac{1}{2}a^2}{T} k=\dfrac{4a^2 \pi-a^2}{2T} k=\dfrac{a^2(4 \pi -1)}{2T} This doesn't equal k=\dfrac{3\pi...

My physics sucks but does gravity affect electical charges inside devices... Does it affect magnetism in coils... I thought it has an affect on anything regardless of how small it is.. right?

A hemispherical bowl of radius a has its axis vertical and is full of water. At time t=0 water starts running out of a small hole in the bottom of the bowl so that the depth of water in the bowl at t is x. The rate at which the volume of water is decreasing is proportional to x. Given that the...