Recent content by hmparticle9

I am going through this course on collision detection: https://siggraphcontact.github.io/ In this link is a PDF called course notes. Scrolling down to section 1.3, called constraints. In this section it is said that we can write bilateral constraints as ##\phi(\mathbf{x}) = 0## and unilateral...

The transitions occur between 5 energy levels, from ##n=0## to ##n=4##. I only included transitions between neighbouring energy levels because #26. I should really include all possible transitions. Well if we limit transitions between shown energy levels from post #43, then from the 5 shown we...

"Can you use this diagram to make a list of the energies of the missing photons that appear as dips?" $$0, 2\frac{\hbar^2}{2I}, 6\frac{\hbar^2}{2I}, 12\frac{\hbar^2}{2I}$$ There are 4 transitions.

So I said, in words, "The red line shows a dip in the intensity of detected radiation. This means that the sample of CO has absorbed energy." And you said that was correct. Okay. So we want a mathematical expression for this energy. Surely this dip in energy has to equal the energy of the...

Are we interested in: $$\Delta \nu = \frac{\hbar^2}{I}?$$

##\hbar## is the same as you. Mass of carbon ##2 \times 10^{-26}## and mass of oxygen ##2.656 \times 10^{-26}## To make the dimensions work out I said: $$\Delta \nu \approx 4 \text{ cm}^{-1} = 12 \times 10^{10} \text{ s}^{-1}$$

Look at post #9. my expression for ##a## is correct

I get ##2.8 \times 10^{-10} \text{m}##

@TensorCalculus @kuruman As part of my maths degree I did vector calculus, classical mechanics, fluid dynamics. Maybe I should get Y and F. I have read Shankar's "Fundamentals of Physics I and II". I did all the problems. These books cover a wide array of physics.

I don't understand. What is wrong with my post #29? $$ a = \sqrt{\frac{\hbar}{4} \frac{m_1+m_2}{m_1m_2}}$$

Okay I just looked at the question again. The distance between the dips looks pretty constant. So we just say: $$\Delta \nu = \nu_j - \nu_{j-1} = \frac{\hbar}{I} \approx 4 \implies I = \frac{\hbar}{4}.$$ We know ##m_1, m_2##. Hence we can get ##a## from the formula $$I = \frac{m_1 m_2}{m_1 +...

I am reading Introduction to Quantum Mechanics by Griffiths. The mathematics and most the physics are going down well, but now and again I hit a complete roadblock. I quite simply don't have the education. Most of the time it is "modern physics". Should I buy a book like "University Physics...

Okay. Is this another 20th century physics thing? Okay. So to finish part c): $$E_{\gamma} = 2 \pi \hbar \nu \text{ and } E_{n+1} - E_n = \frac{\hbar^2}{I} n$$ Hence $$\nu = \frac{\hbar n}{2\pi I}$$

What I meant when I said $$2E_{\gamma} = E_{n+2} - E_n$$ is that two photons are emitted, not one photon with twice the energy.

Where do you get this information from? I am a mathematician by training and so with regards to physics I only really know classical mechanics (maybe we can discuss later). It has taken me a few reads, but I understand your post now. But if I was to be asked what the source of the absorbed...