Recent content by HollowScar

Thank you sir. It was really helpful. Got the answer right to the dot. One last question. So every time ice is mixed with water, or ice becomes water, do we have to also add the water which comes as a result of ice? It is truly wonderful that I received help. I am glad, and indebted to your...

Hi! Sorry to bother you, and I really am indebted by your help, but I have problems understanding. Here is what I do. Heat absorbed by 3kg ice/water = heat released by 30kg water Thus mcΔt (ice) + mLf (ice) + mcΔt (water) = mcΔt (water) However, the problem is somewhere above. I don't put...

mcΔt (ice) + mLf (ice) = mcΔt (water) Temp of ice is (0-(-15C)) Temp of water is (T-50C) Like this? I know that the ice melts, and becomes more water. So only Latent Heat of Fusion is used.

Sorry, I confused it with another question. This is what I did. mcΔt (ice) + mLf (ice) = mcΔt (water) Temp of ice is (0-(-15C)) Temp of water is (49.85C-T) I still did not get the right answer.

Hi! Thank you for the reply. Since ice, and steam eventually reach equilibrium, I would assume that I would have to use Latent heat of fusion, and vaporization. I will have to find the mass mass of steam involved.

Hi! 1. Homework Statement A 3 kg block of ice at -15°C is placed into 30 kg of water at 323K. Calculate the final temperature. It is simple, yet my answer doesn't match up. 2. Homework Equations Oil flows through a heat exchanger at a flow rate of 125 L/min. It enters at 20°C and leaves...