Recent content by hri12

So basically because the book isn't moving in the y direction? That makes sense. Thank you so much btw for all of your help. :)

I think that I might need to use Pythagoras at some point. I know that Fy= F sin(theta) and Fx = F cos(theta)

Homework Statement A man stands on the edge of a deck of width W = 4.8 m. His mass is m1 = 73 kg, and the deck's mass is m2 = 600 kg, uniformly distributed over its surface. The deck is held in place by a support beam which is forming and angle theta = 37 deg with the side of the house...

Why will the normal force be zero? If anything the normal force will be Fn = ma(y) + mg -Fy... I still don't understand.

Never mind. Got it. Thanks everyone! SOLUTION ΣFx = Fx - Ff Fx - Ff = ma(x) Fx - Fn(uk) = ma(x) ΣFy = ma Fn + Fy - mg = ma(y) a(y) = 0 (not sure why...) Fn + Fy - mg = 0 Fn = mg - Fy Fx - (mg - Fy)(uk) = ma(x) a(x) = (Fx - (mg - Fy)(uk) )/m a(x) = 5.2 ((5.2)^2 + (0)^2)^(1/2) = 5.2

Edit: the answer should be 5.20 m/s^2

I know it's not zero because: 1. I already tried with zero and got the wrong answer. 2. It's being pulled diagonally upwards, so both a(x) and a(y) should have a nonzero value.

Homework Statement A book of mass M = .55 kg rests on a table where the coefficient of static friction us = .45. A force, F = 4 N acts on the book at an angle of 15 degrees above the surface of the table. What is the acceleration of the book if the coefficient of kinetic friction uk = .23...