Recent content by hurliehoo

I'd also be interested to know if the OP's solution was along the right lines ...

Hi, thanks for the reply. Basically I'm using this formula to find roots at and Ts = 4 / ( zeta * w(0) ) = 0.06 using w(0) = 133.33 because zeta = 0.5 for a 16% overshoot due to Then I calculate the angle to the desired pole at -66.665 + j115.467 from the first singularity at...

Hi everyone, I would please like some suggestions regarding where my error is, designing a lead compensator with the root locus method for a unity feedback control system where G = [12.5] / [2.5 1 2500]. I want to set the overshoot zeta = 0.5 for an overshoot of 16%, and settling time Ts =...

Regarding my first working, which I posted, of the first (agreed tedious) method I forgot to include the x for b (duh), however the next time I tried I got a similar working to yours ... this didn't work due though, I think because c=-48.75a makes it non-zero. So even when c=0, which it has to...

Ok in that case I am definitely doing something wrong here. Using my understanding of the above method : 1--> max occurs at (3.75, 0.5). Therefore if x = -b / 2a then b = -7.5a 2--> 0 = (7.5^2)a - 7.5a + c therefore c = 7.5a - (7.5^2)a 3--> y = a((x^2) - (7.5^2) + 7.5) 4-->...

Sorry I'm having another look at this and I'm not so sure I understand it now. Some questions about the method ... What does the arrow signify ? How can 0.5 = -0.5/7.5^2 ?

Sorry I didn't make it clear the midpoint maximum for this symmetrical curve is at (3.75, 0.5). Yes it's a parabola though, and your answer is very helpful so thank you very much indeed!

Hi can anyone please tell me how to find an equation from a graph. It's a fairly simple graph. A symmetrical curve with a maximum at y=0.5, and y=0 at x=0 and x=7.5 ... any suggestions appreciated!

Not sure exactly what I'll be doing yet, looking at a few different projects along the lines of power engineering (simple as poss for now lol - in fact any ideas there would be welcome but don't want to trouble everyone too much). Will be sure to post here when I get started and if I run into...

My understanding is that the capacitance of a typical transmission line will increase proportionally to it's length. So in the case of a simple passive LPF circuit, consisting of just the LPF and the transmission line to the load (of infinite impedance), this would in turn mean the cut-off...

Hmm okay this makes it very clear. This is what I was missing earlier. In future similar problems I will try to use this approach. Many thanks for your kindness in taking the time for this.

Mmm... There are some steps missing here which have not been pointed out. I am aware that x=1 is not a factor ... if you read my OP you will see I already know the correct answers. Also, there is no need to fight guys! Please, lol. Actually I do understand at least a few of the fundamentals...

Yeah I get this, thanks for clearing it up though as it's good to have things confirmed ... it just seems a bit of a leap from having a possible solution of x=1, when it isn't correct, to producing a solution of x=2 from somewhere... this is what I'm struggling to understand. I suppose I'm just...

Am I missing something here ... when I factorise (x^2 -1), I get x(x -1/x) and not sure what that means ..?

I tried to do that (using the quadratic formula) and it didn't work. :( The reason was that b=2/x which only gave one correct answer. I actually tried this in two different ways and each time only one solution was correct.