Recent content by huyichen
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Graduate Is the Tensor Product Associative?
It is a well fact that tensor product is associative up to isomorphism, but how should I use Universal property(you know, diagrams that commute) to show that it is true?- huyichen
- Thread
- Product Tensor Tensor product
- Replies: 2
- Forum: Linear and Abstract Algebra
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Graduate Maps B2->S2 Define F+ & F-: Show Int w S2 = Int F+*(w) B2 - Int F-*(w)
But as F- and F+ agrees on equator, then the limit indeed hold, right?- huyichen
- Post #7
- Forum: Differential Geometry
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Graduate Maps B2->S2 Define F+ & F-: Show Int w S2 = Int F+*(w) B2 - Int F-*(w)
Actually, this is problem 14-6 from Introduction to Smooth Manifolds, Lee's book, we can not directly talk about the boundary because F+, F- is continuous but not smooth up to the equator. And the integrand is unbounded, but if we interpret in an appropriate limiting sense, then we can show...- huyichen
- Post #5
- Forum: Differential Geometry
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Graduate Maps B2->S2 Define F+ & F-: Show Int w S2 = Int F+*(w) B2 - Int F-*(w)
Justify means that we can indeed replace Integral F^*w with the limit integral as R--> 1- huyichen
- Post #3
- Forum: Differential Geometry
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Graduate Maps B2->S2 Define F+ & F-: Show Int w S2 = Int F+*(w) B2 - Int F-*(w)
Define F+:B2->S2 by F+=(u,v)=(u,v,sqrt(1-u^2-v^2)) and F-:B2->S2 by F-=(u,v)=(u,v,-sqrt(1-u^2-v^2)) Then to show that Integral of w on S2=Integral of F+^*(w) on B2-Integral of F-^*(w), why do we need to justify the limits(As the integral on the right hand side are defined as limits as...- huyichen
- Thread
- Replies: 7
- Forum: Differential Geometry
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Graduate Nonvanishing section for direct sum of Mobius band
For a direct sum of Mobius band, it is trivial if it has two linear independent nonvanishing sections. I have the following as my sections: s1=(E^(i*theta), (Cos(theta/2), Sin(theta/2)) s2=(E^(i*theta), (-Sin(theta/2), Cos(theta/2)) Clearly, the above sections are linearly independent and...- huyichen
- Thread
- Band Direct sum Section Sum
- Replies: 1
- Forum: Differential Geometry
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Graduate Vector field as smooth embedding
We can show that any vector field V:M->TM(tangent bundle of M) is smooth embedding of M, but how do we show that these smooth embeddings are all smoothly homotopic? How to construct such a homotopy?- huyichen
- Thread
- Field Smooth Vector Vector field
- Replies: 2
- Forum: Differential Geometry
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Graduate How to show that a transverse intersection is clean, but not conversely?
If K and L are embedded manifold of M, and T_p(K intersect L)=T_p K intersect T_p L and K intersect L is again a embedded manifold , then we say K intersect L is clean- huyichen
- Post #3
- Forum: Differential Geometry
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Graduate How to show that a transverse intersection is clean, but not conversely?
How to show that a transverse intersection is clean, but not conversely?- huyichen
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- clean Intersection Transverse
- Replies: 4
- Forum: Differential Geometry
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Graduate Number of Nondegenerate Zeros of Vector Field Bounded
"if a vector field has only nondegenerate zeros then the number of zeros is bounded" With no idea how to show that without using Poincare-Hopf Theorem. Any proof possible without using any concept from algebraic topology?- huyichen
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- Bounded Field Vector Vector field
- Replies: 2
- Forum: Differential Geometry
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Graduate Smooth covering map and smooth embedding
Now F:S^2->R^4 is a map of the following form: F(x,y)=(x^2-y^2,xy,xz,yz) now using the smooth covering map p:S^2->RP^2, p is the composition of inclusion map i:S^2->R^3 and the quotient map q:R^3\{0}->RP^2. show that F descends to a smooth embedding of RP^2 into R^4. Is the problem asked to...- huyichen
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- Map Smooth
- Replies: 1
- Forum: Differential Geometry
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Graduate Intersection of complex sphere and cone
Show the intersection of complex sphere (|z1|^2+|z2|^2+|z3|^2=1) in C^3 and the complex cone (z1^2+z2^2+z3^3=1) in C^3 is a smooth submanifold of C^3. I am trying to do it using regular level set, but I am not sure which one of (1,0) or (1,1,0) should be set to be the regular value?- huyichen
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- Complex Cone Intersection Sphere
- Replies: 1
- Forum: Differential Geometry
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Graduate Proving Pushforward Product Isomorphism: M1 x ... x Mk to M1 + ... + Mk
But, don't we need to take component functions of arbitrary X into account?- huyichen
- Post #3
- Forum: Differential Geometry
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Graduate Smooth manifold and constant map
Suppose M and N are smooth manifold with M connected, and F:M->N is a smooth map and its pushforward is zero map for each p in M. Show that F is a constant map. I just remember from topology, the only continuous functions from connected space to {0,1} are constant functions. With this be...- huyichen
- Thread
- Constant Manifold Map Smooth
- Replies: 2
- Forum: Differential Geometry
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Graduate A question about vector space manifold
You mean change one of the dependent row into a row that is not in the span of k independent rows? In that way you can change the rank?- huyichen
- Post #9
- Forum: Differential Geometry