Recent content by i2837856393

your velocity is the derivative... v= 10-3.72t there are going to be 2 times when the rock is on the ground. one at time zero and one at the 2nd time... which is 10/1.86t 1.86t2-10t=0 1.86t=10 t=0 and t= (about) 5.37 to find the velocity you plug in 5.37 into the derivative...

i'm sorry you're right... that should be pi/2 - pi which is -pi/2 i accidentally added them... yea. then you and i are in agreement. i guess the teacher made a mistake. I've spent hours and this was the only solution i came to.

Homework Statement \intydx + zdy C where C is the part of the helix r(t)=(sin t)(i) + (cos t)(j) + t(k) and 0 < t < pi (those should be greater than or equal to signs) \int(cost)(cost)-t(sint) \int(1+cos 2t)/2 - t sint with limits from zero to pi. this then equaled to...