Recent content by icefirez
-
I
The limit as x approaches 1 of x / ln (x)
sorry yes I'm wrong... but you don't have to be rude and I know that you have to write log instead of "LAG" but please it's not the end of world.- icefirez
- Post #9
- Forum: Calculus and Beyond Homework Help
-
I
The limit as x approaches 1 of x / ln (x)
well i don't think so maybe I'm wrong but let's see lim as x->1 (x/lnx) now me remove the natural lag lim as x->1 ( e^x/ x) so as X approaches 1 we get lim x->1 (e^1/1)=e :) and yes it's legit :)- icefirez
- Post #5
- Forum: Calculus and Beyond Homework Help