Recent content by ifeg

Thank you for the tip. i tried it though and it didn't quite work out. but i will keep playing with it and see.

This is what i am unsure about. How do i go about showing that \(f(t)=\frac{t \sin(\omega t)}{2\omega}\) is a solution of: \(my''+ky=\cos(\omega t) \)? i don't understand the resonance and the amplitude aspects..

No, i don't think there's anything about a particular diff equation. i came across a question that asked just to find the general solution, but it had come after some other questions that asked to solve some diff equations, so i was wondering what, if any, was the difference between the two. I...

If you are asked to solve a differential equation (single order) that has no initial values, then you separate if possible, integrate and include the Constant of integration, leaving the response in terms of the dependent variable, right? So if you are given a single order differential...

Re: Solving differential equations Oh yeh, it's $$ y = \frac{Ae^x}{1+Ae^x} ; A=e^c $$ (it was the wee hours of the morning, and i hadn't slept since the night before that so I wasn't 100% )Thanks again

Re: Solving differential equations solving for $y$, i got $$ y = \frac{Ae^x}{1-Ae^x} ; A=e^c $$

Re: Solving differential equations How did the minus sign (log y - log (1-y) ) get there? that's where i went different. I don't follow.

I am having a problem. I think i went well in decomposing the partial fraction and integrating, however my answer leaves me concerned. please help if i have gone wrong. Solve: dy/dx + y^2 = y. after taking partial fractions, i simplified this to: (1/y + 1/ (1-y) ) dy = dx and i integrated...