Recent content by ilario980

I expected the last two diagrams to be just rotated, but they follow the Lorentz transformation so do not agree space/time measurements

at first glance the Lorentz transformations say that in order to agree on the constant c we must disagree on the measure of length and time; I will study this in more detail later, thank you very much for your answers

or it could be a flight recorder instead of a camera to avoid ligth delays

Okay, I need to study the theory, what seems like a paradox to me is that both cameras show that time flows at the same speed after mars landing

yes, i used ##t_{actor}## as time on actor clock , ##d\tau_{actor}## is the wright notation let's put this way, suppose that enterprise has on board 2 ultra wide camera; at departure time all clocks signs 00:00:00 and camera 1 focuses on a big clock on mars signing 00:00:00 when enterprise...

nope, just to share some thinking... God bless you all

at t0 ship starts and all clock signs 00:00:00; when the ship is near mars tearth=tmars = 00:30:00 t ship = t spock =00:29:00 then spock leaves the ship tearth=tmars = 00:31:00 t ship =~ 00:29:30 t spock = ? tspock should tick at the same rate of mars clock and a slower tick than ship...

just a bit of math: tspock< tship< tmars tspock = tmars

Thank you very much for your replies; my doubt is that Mr. Spock clock cannot be aligned with Mars clock since it should be slower than ship. I will read about relativity of simultaneity, at the moment I'm busy Ilario M.

ok, but Mars clock should be aligned whith earth clock so Enterprise should see events of Mars faster, not slower; what's wrong?

suppose the enterprise departs from planet earth on a mission the the other side of the milky way at 90% of the speed of light; since time is dilated while cpt Kirk drinks coffe on planet earth some time passes (let's say 1h). Approaching mars captain Kirk orders dt. Spock to land on Mars with...

you have got to search for "discrete calculus" the general rule (fundamental theorem of discrete calculus) is: if g(n+1)-g(n)=f(n+1) then \sum^{b}_{n=a}f(n)=g(b)-g(a-1) for example, the partial sums (you call it "general term") for the geometric series are: f(n)=a...

in my paper i intentionally leaved some points without explanation; this to avoid that someone attibute himself the discovery of the pi-tilde function(if this has offended in some manner i apologize). suppose we want to know an approximation of partial products by theorem 1 we can say that...

partials products are defined on integers (as partial sums). Theorem 1 says that if f e g are two functions such that: \frac{g(x+1)}{g(x)}=f(x+1) then the partial product from a to b of f(x) is: \frac{g(b)}{g(a-1)} to verify this theorem for f(x)=x then you have got to use the...

using the Pi-tilde function i have classified numbers in the following way:if the left limit of Pi-tilde(x) is zero then x is a not prime number; if the left limit of Pi-tilde(x) is not zero then if the right limit of Pi-tilde(x) is zero then x is a prime number else...