Recent content by ilovecake

using elimination by subtraction, solving for x: ax+by=e cx+dy=f (ax+by)-(cx+dy)=(e-f) ax-cx +by-dy=(e-f) (a-c)x=(e-f) x=(e-f)/(a-c) Nevermind, I just realized that it's to make the coefficients of y the same. (ad)x+(bd)y=(de) (cb)x+(bd)y=(bf)

Homework Statement A general system of linear equations is ax+by=e cx+dy=f where a,b,c,d,e,f are constant values. a)Use elimination to solve for x and y in terms of a,b,c,d,e,f. b)Are there any values that a,b,c,d,e,f cannot have?The Attempt at a Solution For part A, I got x=(e-f)/(a-c)...