Recent content by imana41

then the nearest point is (0,0,1)

please help me more

if http://latex.codecogs.com/gif.latex?x^2+y^2+z^2=1 we get x(t)=cost , y(t)=sint and z(t)=1 but for http://latex.codecogs.com/gif.latex?(x-1)^2+(y-1)^2+(z-1)^2=1 I'm not know ??

i know F=(M,N,P)=(yz,xz,xy) and c is on closed curve i think i should use but the euqals is zero I'm not sure . plaese help

thanks for your help

i can't say http://latex.codecogs.com/gif.latex?\int_{-1}^{1}\int_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}}ydydx = http://latex.codecogs.com/gif.latex?4\int_{0}^{1}\int_{0}^{\sqrt{1-x^2}}ydydx=\frac{4}{3}

this Q want to check Stokes' theorem ? for http://latex.codecogs.com/gif.latex?F=(x^2,xy,-z^2) and surface http://latex.codecogs.com/gif.latex?x^2+y^2+z^2=1 and http://latex.codecogs.com/gif.latex?z\geqslant%200 i should equal http://latex.codecogs.com/gif.latex?\oint%20Mdx+ndy+pdz with...

pleaes help me about this solve on curve c that is the bigest circle of sphere http://latex.codecogs.com/gif.latex?(x-1)^2+(y-1)^2+(z-1)^2=1

distance from (x,y,z) to (0,0,0) is http://latex.codecogs.com/gif.latex?\sqrt{(x-0)^2+(y-0)^2+(z-0)^2} your purpose is http://latex.codecogs.com/gif.latex?d=\sqrt{x^2+y^2+x^2y^2+2xy+1} and then d'=0 but ratio to x and y then x=0 and y=0 and z=1 and the point =(0,0,1)

thanks the the answer of integral is

hi pleaes help me about this http://latex.codecogs.com/gif.latex?\int_{1}^{\infty%20}e^{-x^2+2x}dx i know the http://latex.codecogs.com/gif.latex?\int_{0}^{\infty%20}e^{-x^2}dx is http://latex.codecogs.com/gif.latex?\sqrt{%20pi}/2 but can't solve above integral !?

thanks plaese help about this find a point on surface z=xy+1 that Nearest point to (0,0,0) ?

your purpose is ?http://latex.codecogs.com/gif.latex?\frac{\bigtriangledown%20f}{\left%20|%20\bigtriangledown%20f%20\right%20|}=(0,0,1) or not . pleaes explain more