Recent content by imogen89

yea that's what i thought, but it says to plug the circuit into analogue in on the circuit diagram [half way down the page that the other guy gave me a link for]...where is that wire going. or do i not even need to know...

now, i am doing the same planning excersise as einstein was---> and i was wondering, do you think that it would be enough to do the experiment you mentioned earlier where you just attatch a DVM on mA setting to the photocell, or whether it would give more of a valid conclusion to do the thing...

ok now it did come up. I'm goign to be quiet and do my physics work now. I'll probably be back though. i am not getting what analog in means...

ok i just reposted something and it didnt come up. i said... oof, that's the most helpful thing I have seen all day:):):)

oof. that's the most helpful thing i have seen all day:):):)

does that question even make sense? also, it says in a [much] earlier post that the current flows <i>out</i> of the cathode. doesn't current usually go <i>into</i> the cathode?

yes, i read that already [all of my references seem to be from wikipedia:)], but i don't understand, "photocurrent is the current that flows through a photosensitive device"---does this mean that it is just normal current when it flows out of the photocell and into the wires, because it is no...

i am so going to fail this...

and if anyone has a circuit diagram [a simple one, all of the ones on the links you have put up make me want to cry] of what this should look like, that would be lovely:)

haha:smile: what exactly is photocurrent. this is probably really obvious, but i am terrible at electronics, and really not understanding any of this.