Recent content by imy786

Thanks but the q did not ask for calculation Just a description

Homework Statement Describe the energy conversions of a device which is on a spring which is compressed then released and then spring bresks the device bounces up in the air. Homework Equations ignore air resistantance The Attempt at a Solution The device goes from strain energy...

why isn't anyone responding?

is this correct?

Find the period of rotation T = 2 ∏ / omega = 2∏/523.6 = 0.012 seconds

Would the highest point speed be V= O meters per second in the y direction of this projectile motion

for vertical component= u= usin theta right and for horizontal u= ucos theta

can someone PLEASE confirm part 3 and 4 to my solution is correct! Thanks

can someone PLEASE confirm part 3 and 4 to my solution is correct! Thanks

Homework Statement a ball moves at 5000 rpm (revolutions per minute). Their radius is 4 cm. (i)Determine the angular speed in radians per second. (ii) Find the period of rotation (iii) Find the linear speed of a point on the outer ball (iv) Find the linear acceleration of a point on...

4.Use the answers to parts (1) and (3) to calculate the magnitude and direction of the ball’s initial velocity and of its velocity at the highest point. answer to part (1) and (3) ucosθ=24.3 m/s usinθ =28.34 m/s magnitude=√((24.3)&^2 + (28.34)^2 = =√(590.49 + 803.16) = 37.33 m/s tanθ =...

3.Hence find the horizontal component of the ball’s initial velocity U=U sinθ a=0 s=70 (correction) v=0 t=2.47 seconds s=ut+(1/2)a(t)(t) 70=U sinθ (2.47) + 0 70/2.47 = usinθ =28.34 m/s (so this is the solution for part 3)

duplicate

4.Use the answers to parts (1) and (3) to calculate the magnitude and direction of the ball’s initial velocity and of its velocity at the highest point. answer to part (1) and (3) ucosθ=24.3 m/s usinθ =12.146 m/s magnitude=√((24.3)&^2 + (12.146)^2 = =√(590.49 + 147.53) = 27.16 m/s tanθ =...

3.Hence find the horizontal component of the ball’s initial velocity U=U sinθ a=0 s=30 v=0 t=2.47 seconds s=ut+(1/2)a(t)(t) 30=U sinθ (2.47) + 0 30/2.47 = usinθ =12.146 m/s (so this is the solution for part 3)