Recent content by indr0008

can u show us ur calculation? because if u have found the speed at the botton of the hill, then u are supposed to be able to find the rest of the question

In your free body diagram, do u have these 3 forces: the weight od the car, the normal force exerted by the ground, and the friction force? :)

ok, u are done basically, u can use any of the masses actually, so let's say we concentrate on the heavier one the heavy mass' equation of force will be: -Mg+T=-Ma -(4 kg)(9.8 m/s^2)+T=-(4kg)(5.88 m/S^2) that's it, u've found it :) can u find it now using the smaller mass? :)

u can use the law of energy conversion here, what do u think the initial energy that the man has?

can u draw the force diagrams of each mass? that will help u a lot :)

can u imagine what will happen to the car?

that means that if the angle that enters the rod is bigger than that, the ray will be refracted that's all

as u see from ur picture, if the rod is very long, what will happen to that ray in the picture?

can u elaborate more on the answers? why do u think they should be included?

try drawing the diagram, u'll see :)

the problems specifically says that it is in vacuum, so wind, air density and such is a no go :)

the other distance is 3.76 e8

done, give me cookies :D

actually it is easier to draw the force diagram first :)

i'm not really familiar with this 'curved axis' thing, but actually ur first equation is derived from the latter two