Hi, I would like some help in proving the following identity:
\sum_{x=0}^{n}x^3 = 6\binom{n+1}{4} + 6\binom{n+1}{3} + \binom{n+1}{2}
I tried doing it by induction but that did not go well (perhaps I missed something). Someone told me to use the fact that \binom{x}{0}...