Recent content by inovermyhead

*Bangs Head on Desk* Okay. So it's 50... Thank you for all of your help, I really appreciate it.

Down right is what I assumed it was, which makes sense to me, at the 230 from the +y-axis, but it wasn't right.

Errr... okay: I know that one is: (2.5x10-8)(4x104)(2)(sin(50)) **I had messed up my km to m conversion, and feel remarkably stupid*** and I know that three is: (2.5x10-8)(4x104)(2)(sin(90)) but I'm still unsure what to do with part 2. I thought it would be 230° from the y-axis and was...

Thank you for the quick link, I hope I fixed all the formatting errors. About the problem: What happens to the force if it isn't "flowing" in that direction? I get that it's not zero but if it isn't in that direction, what's going on with it? I know the force is F=|q|VBsin(θ), but what are...

Homework Statement A particle with a charge of −2.50×10-8 C is moving with an instantaneous velocity of magnitude 40.0 km/sec in the xy-plane at an angle of 50.0° counterclockwise from the +x axis. 1) What is the magnitude of the force exerted on this particle by a magnetic field with...