Recent content by inuka00123

in the problem 100 cm is obviously equal to 1m, and 10cm is equal to 1/10m and it is equal to 0.1m, but when you take the square of the 10cm it is obviously does not equal (1/10m)² nor (0.1m)², therefore (10cm x 10cm ≠ 1/10m x 1/10m = 0.1m x 0.1m), then to what 10cm x 10cm is equal to in meters...

how liquid based systems e.g. hydraulic systems, can change the force which applied on it is smaller pistons, and transfer much force to a larger piston in area, my textbooks says 1:10 ratio hydraulic system can deliver ten times the force applied on the smaller piston to the large piston. it...

I tried different equations, every one seems give a = 8.8 rad/s² and for displacement 330 radians, because I tried to plug the answer to different equations and got the same solution, I think it is correct, thank you!

I am really confused, if I find the acceleration using ω₁ = ω₀ + at equation and plug that onto another equation or I can just use the θ = 1/2 (ω₁ + ω₀)t equation, right?, my textbook is really confusing, and 1/2 (ω₁ + ω₀) would be the average speed, or avg angular velocity, or...

is it wrong to just use the θ = revolutions per second x 2π, after plugging the equations, θ₁ = rev x 2π = 7 x 2π = 44 radians θ₂ = rev x 2π = 14 x 2π = 88 radians *to get the θ between acceleration I subtract θ₁ from θ₂, and got 44 radians. when the acceleration come into...

yeah, I saw that it means I need to multiply it by 2pi to get to the radians, can you give me the answer for this question, it would help me to compare my solution and what is correct to find what I am missing more

I assumed first the car is travelling 7 rad/s then accelerated to 14 rad/s in 5 seconds, after plugging the variables, I got θ = 35, I must be wrong about this calculation, can someone explain, if wrong give me the way of calculation please?

does this mean to find tanα you need to divide X/Y or divide (X/Y)/tan to find α?

I like the idea there is a anything anywhere source to help learn things that are hard to understand, for example I did not understood anything my school taught, then I went on youtube like every time and thought, why not look up on youtube, and I found a video and understood it, but I still...

did not thought about that, thank you.

I will be thrown forward, the minus acceleration can be thought as slowing down, but I can not understand how slowing down affect my weight, like in a elevator, slowing down causes weight to be less.

a imaginary vehicle that travels vertically is deaccelerating at the rate of 5ms/s in upward direction. I understand that when the vehicle is accelerating upwards, at the rate of 5ms/s, the weight of the people inside the vehicle increases, respect to the newtons third law, peoples have a...

I undetstand.

imagine a person pushing a 10Kg cardboard box with 20N of force toward a 5Kg cardboard box, with the second law we can calculate it is moving at 2ms/s acceleration toward the 5Kg box, relative to the 10Kg box we can say the 5Kg box is moving toward the 10Kg box with 2ms/s acceleration with a 10N...