Oh, I see what you're saying now. Actually, I sort of got the impression that she was showing off. And no, I don't give a **** what her mark is or what the other students' marks are either. Even the person with 67 could get his/her mark up.
In my class, there is a person who was doing...
Does this sort of have something to do with a "Pair's Production"? I'm still in Physics 30, and we sort of learned something about this. I don't have my notes anywhere with me, but I'll explain what I remember by memory.
Annihilation: When matter and antimatter collide, matter is converted...
In my Chemistry class we are doing some old diploma review questions in order to prepare for this year's Chemistry diploma. I have answered almost all of the questions.
It says:
The above apparatus (I'll explain the diagram later) was used to determine experimentally the molar enthalpy of...
I'm stuck on this question and I'm not sure where to start. :confused:
A positively charged ion (m = 3.34 x 10^-26 kg) was accelerated from rest through a potential difference of 1.66 x 10^4 V. This ion now enters a region where there is a magnetic field (B = 3.20 x 10^-2 T) that is...
Question: The nearest star, Alpha Centauri A, is 4.07 x 10^16 m from Earth.
a. How many light years is it away from Earth?
b. What is the advantage of stating stellar distance in light years rather than meters?
Part A, I got stuck because I don't know wheither to use the distance from the...
Hello everyone. I have a question and I'm not sure how to answer it.
Q: Name the types of electromagnetic radiation that are used to obtain images of Earth from space. In each case include a concise description as well as the frequency or wavelength range.
BTW, I think I'll probably be...
Thank you cookiemonster for the help. I've solved the question. Sorry for getting back to you so late. By the way, I need help again...here's the question:
If you take your electric razor, which has a resistance of 440 Ohms to Europe, where the voltage is twice as high, what factor will...
How do I do these 2 questions:
1. Calculate the net gravitational field strength due to the moon and Earth halfway between Earth (Mass of earth=5.98 times 10 to the 24 kg) and the moon (Mmoon=7.349 times 10 to the 22 kg). The moon's mean orbital radius is 3.845 times 10 to the 8 meters.)...
I was just wondering. How come the gravitational field strength of the sun is much larger than the gravitational field strength of the moon at when you calculate both values at Earth's position?