Recent content by Isti0503

Alright thank you.

So if I use those formulas I will get: F=Uk*mg*(r1/r2). So r1 is the radius of the axle and r2 radius of the wheel.

Alright but then out off those two forces (at the rim, and the frictional force), which force am I looking for?

Well the force of friction will be the coefficient times mg. Right?

Ok so the normal force would be just mg, the frictional torque that creates would be the tangential force at the axle times the radius of the axle, the force that will overcome that torque is basically the radius of the wheel times the tangential force to the rim right? What do you mean by the...

Homework Statement Estimate the rolling resistance force for a 75gram vehicle with axle friction coefficient of 0.2 if the wheel is 40mm diameter and the axle 2mm diameter. I am having trouble with applying the axle friction coefficient. I could not find a similar problem online. Basically...