Recent content by jai6638

Q) A 3 g bullet traveling at a speed of 400m/s enters a tree and exits the other side with a speed of 200 m/s. Where did the bullet's lost KE go, and what was the energy transferred? This is an example prob from my book which says: Change in KE+Change in Internal Energy=0 Hence, Change in...

hey thanks for your help.. I needed help with some other probs .. i'd appreciate your help Water runs into a conical tank at the rate of 2 cubic feet per minute. The tank stands point down and has a height of 10 feet and a maximum radius of 5 feet. How fast is the water level rising when the...

Hey.. I'd appreciate it if you could guys could verify my answers for the following questions.. Find dy/dx: 1) y=arcsin(2x) y'= (2)/sqrt(1-4x^2) 2) y=arctan(x^2) y'= 2x/(1+x^4) 3) 3sqrt(x)=sqrt(y) dy/dx=( 3.(x)^(-.5) / (y)^(-.5)) 4) xy+y=x dy/dx = (-y)/(x+y) 5) e^cosy=x^3 arctan...

Ahh I see.. alright cool... thanks..

ahh I see.. there's probably an error in the textbook then... Once again, thanks much :) .. appreciate your help..

the answer still remains 68 m/sec though unless I am doing something wrong again.. doh..

nevemrind.. I got 8.37 m/sec... For C) i used v^2= v0^2-2a(y-y0) v^2= (8.37)^2 - 19.6( 235) v= 67 m/sec and not 97m/sec what am I doing wrong? I apologize for askin you so many qustions.. got a test tomorrow so am trying to make sure I...

well I get the v0 as 16.20 m/s and not 8.37 s ... I solved the following equation: 0=235+(6.124)v0 - 4.9 ( 6.124)^2 to get v0 ..

I see .. cool thanks.. Another questoin: A rescue plane wants to drop supplies to isolated mountain climbers on a rocky ridge 235 m below. If the plane is traveling horiszoontally with speed of 250 km/hr ( 69.4m/s) . A) how far in advance of the receipients must the goods be dropped...

it says that the components are -2450 , 3867 and 2450... Why is the first 2450 a negative? Would it be possible for you to tell me what the diagram would look like? i'd really appreciate it. thanks much.

your right... it corresponds with textbook answer.. but why is it the Z axis? and not a right triangle with the two sides being 4580 and 2450? thanks

The summit of a mountain, 2450 m above base camp, is measured on a map to be 4580 m horizonttally from the camp in a direction 32.4 degrees west of north. What are the components of the displacement vector from camp to summit? What is its magnitude? Choose the x-axis east, y-axis north and z...

Even though I did this and got the answer, I had a question.. Is using the components of 90-33= 57 degrees north of east correct? shouldn't it yield a different result than 33 degrees east of north? or is it one and the same thing? Thanks much for your help.

Please correct me if I am wrong but I do not believe you have to divide into x and y components for the first problem.

well I have a feeling that my diagram is wrong and hence I wasnt referring to it when I edite dthe answers.. My diagram is setup like this: starting from the same origin, I have three lines: a, b , c ... A goes north of east at 25 degrees. B goes east of north at 33 degrees and C goes 56...