Recent content by jain_arham_hsr
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Chain rule and division by zero
My approach is as follows: a = dv/dt = (dv/dx) * (dx/dt) = (dv/dx) * v Putting v = 0: a = (dv/dx) * 0 = 0 m s^(-2) But, what I don't understand is this: If v=0, then dx/dt must also be 0. Consequently, dx must also be 0 at that particular instant. But, we are writing acceleration as (dv/dx) *...- jain_arham_hsr
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- Differential calculus Kinematics
- Replies: 12
- Forum: Introductory Physics Homework Help