Recent content by jaksa

I got ##F=0.3849 \cdot F_{0}## and the approach from my first post gave me formula of: $$\dot{R} = \frac {2 \cdot 0.3849 \cdot F_{0} AR^2_{0} v} {GMm} \approx 3.5 \frac m s$$

With canted at an angle sail I have: The formula for F: $$F = F_{0} \cdot cos^2(\alpha),$$ tangential component: $$F_{t} = F_{0} \cdot cos^2(\alpha) \cdot sin(\alpha)$$ Now I find for what ##\alpha## the ##cos^2(\alpha) \cdot sin(\alpha)## is maximum then calculate the rate of potential energy...

There was a hint in the problem: "Maximize the power transferred to the spacecraft by radiation pressure." I also assumed that the sail always stays perpendicular to the radius. Due to radiation pressure, force is exerted on the sail.

I wrongly assumed that total energy at ##R## will be of form ##E_{total} = - \frac {GMm} {2R}##. With solar sail the orbit will no longer be a circle. I will try to solve EOM: $$m \frac {d^2R} {dt^2} = -F_{G} + F_{S},$$ then get the radial component of velocity, that should be it.

In order to change the radius, additional energy is required, the total energy of mass m on a circular orbit is given by: $$E_{total} = - \frac {GMm} {2R},$$ The change in energy between orbits ##R## and ##R_{0}## is: $$\Delta E_{total} = \frac {GMm} {2} \cdot \left( \frac 1 R_{0} - \frac 1 R...

Some time after my PhD I decided to study physics (again) on my own and with my own (maybe bit slow) pace. I do not work in the field, changed to IT but I kept physics as my hobby. The self study really brings me joy, can take it slow, rethink with no rush on terms, exams, etc. Currently, trying...