Recent content by james11

I figure it out My brain must have gone walk abouts for the past week! j

Yes i have managed to rearrange to and i have that part. The next part of the question ask to rearrange another equation that is similar to the original equation given but instead it is 2pieG/3*P^2*R^2 and then find R I have managed to get R = Sqrt3P/2pieGP any help would be great in...

I have divided by this but i don't seem to get the radius i am given I end up with R = SQUARE ROOT P2G/3 am i on the track or have mixed up the equation j

P= \frac{\2pieG}{3}p^2r^2 2\pieG}{ \2pieG

P= \frac{2\pieG}{3}p^2r^2

P= \frac{2{\p}{G}{3}p^2r^2

P= \frac{2{\p[G]}}{3}p^2r^2 P= \frac{2{\p[G]}}{3}p^2r^2

OK let's try again! P= \frac{2 {\p} G}{3}p^2r^2 i need to find r = just having trouble where to start! I have tried a few times. just a bit stuck! Any help would great ! Thanks in advance

[tex]P= \frac{2 {\p} G}{3}p^2r^2[\tex] i need to find r = just having trouble where to start! I have tried a few times. just a bit stuck! Any help would great ! Thanks in advance

P= \frac{2{\pG}}{3}p^2r^2

P= \frac{2\pG}{3}p^2r^2

just testing! P= \frac{2 {\p} G}{3}p^2r^2

Lets try again! P= \frac{2 \p G}{3}p^2r^2

Lets try again! [tex]P= \frac{2 \p G}{3}p^2r^2[\tex]

test! P= \frac{2 \p G}{3}p^2r^2