Recent content by janex
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How to find magnitude of two forces
Yes, thank you for this! I had actually gone off of a sketch I had, and it was not accurate. After you had mentioned so, I looked back at the homework and it's sketched the way you have it. Thanks for all your explanations!- janex
- Post #22
- Forum: Introductory Physics Homework Help
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How to find magnitude of two forces
Thanks for all your help TSny!- janex
- Post #20
- Forum: Introductory Physics Homework Help
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How to find magnitude of two forces
Ye I think once I get a good look at this tomorrow, it'll make better sense. As far as I can see, the vector does move in a negative direction towards F2.- janex
- Post #19
- Forum: Introductory Physics Homework Help
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How to find magnitude of two forces
I It is pointing up- janex
- Post #17
- Forum: Introductory Physics Homework Help
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How to find magnitude of two forces
340 N @ 25 degrees is below x-axis. 414 N @ 9 degrees I above x-axis.- janex
- Post #13
- Forum: Introductory Physics Homework Help
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How to find magnitude of two forces
.9876883- janex
- Post #11
- Forum: Introductory Physics Homework Help
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How to find magnitude of two forces
I've switched the mode to degrees, but still am getting the wrong answer. :(- janex
- Post #9
- Forum: Introductory Physics Homework Help
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How to find magnitude of two forces
So what you are saying Tsny is that I should convert the answers to radians?- janex
- Post #7
- Forum: Introductory Physics Homework Help
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How to find magnitude of two forces
Steamking, 414 x cos 9 degrees = - 377.2.- janex
- Post #5
- Forum: Introductory Physics Homework Help
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How to find magnitude of two forces
Two forces are given and are applied to a car in an effort to accelerate it: 414N at 9 degrees and 340N at 25 degrees. What is magnitude of the resultant of the two forces? Answer in units of N. So I've added together X= (414cos9) + (340cos25), and got -40. For the Y, Y= (414sin9) +...- janex
- Thread
- Forces Magnitude
- Replies: 21
- Forum: Introductory Physics Homework Help