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Two forces are given and are applied to a car in an effort to accelerate it: 414N at 9 degrees and 340N at 25 degrees. What is magnitude of the resultant of the two forces? Answer in units of N.
So I've added together X= (414cos9) + (340cos25), and got -40.
For the Y, Y= (414sin9) + (340sin25)=125.
I took square root of (-40)^2 + (125)^2, and got 131.24.
However, that is not the correct answer. What am I doing wrong? Help please?!
So I've added together X= (414cos9) + (340cos25), and got -40.
For the Y, Y= (414sin9) + (340sin25)=125.
I took square root of (-40)^2 + (125)^2, and got 131.24.
However, that is not the correct answer. What am I doing wrong? Help please?!