the sticks in total ar 40 grams, so the compelete rail is 40 grams.
the 10 are the 10cm, it should be N cm indeed, my mistake.
the 10 cm comes from the centre of gravity.
as the centre of gravity acts from the middle of the stick (80cm /2 = 40cm so 10 cm to the left of the string)
0.4 * 10 (Fg of the yellow piece) + 0.6* 50 = 34 N cm
this is already in the first post ;)
calculate Fg of weight A (0.06kg * 10 = 0.6N)
and M= F * d
so M = 0.6 * 50 = 30 N cm
for the stick itself
Fg = 0.04 * 10 = 0.4N
0.4 *10 = 4N cm
30+4 = 34N cm
ok
I might have the solution.
please somebody confirm if I'm doing the right thing. ;)
So the Mccw = 34 N cm
Mccw = Mcw = 34 N cm
F=M/distance F= 34/30 = 1.13333333333334 N
so the weight has to be 113 grams.
The stick is 40 grams, so B + C = 73 grams
The sticks centre of gravity acts...
Homework Statement
Homework Equations
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The Attempt at a Solution
I've tried to calculate moment counter clockwise,
0.4 * 10 (Fg of the yellow piece) + 0.6* 50 = 34 N cm
this is how far I got...
I don't know how to proceed from here on..
please help ;)
and sorry for my english
and sorry if...