Recent content by Jasbroek

the sticks in total ar 40 grams, so the compelete rail is 40 grams. the 10 are the 10cm, it should be N cm indeed, my mistake. the 10 cm comes from the centre of gravity. as the centre of gravity acts from the middle of the stick (80cm /2 = 40cm so 10 cm to the left of the string)

0.4 * 10 (Fg of the yellow piece) + 0.6* 50 = 34 N cm this is already in the first post ;) calculate Fg of weight A (0.06kg * 10 = 0.6N) and M= F * d so M = 0.6 * 50 = 30 N cm for the stick itself Fg = 0.04 * 10 = 0.4N 0.4 *10 = 4N cm 30+4 = 34N cm

ok I might have the solution. please somebody confirm if I'm doing the right thing. ;) So the Mccw = 34 N cm Mccw = Mcw = 34 N cm F=M/distance F= 34/30 = 1.13333333333334 N so the weight has to be 113 grams. The stick is 40 grams, so B + C = 73 grams The sticks centre of gravity acts...

wops sorry my mistake.. The "first" bar isn't 20cm on the right, but 30... updating picture atm

Homework Statement Homework Equations - The Attempt at a Solution I've tried to calculate moment counter clockwise, 0.4 * 10 (Fg of the yellow piece) + 0.6* 50 = 34 N cm this is how far I got... I don't know how to proceed from here on.. please help ;) and sorry for my english and sorry if...