Recent content by Jasmin99

Thanks for the help everyone! I have figured it out now.

Here is my work: Fnet= 150-(17)(2.3) Fnet= 110.9N Fnet=uFn 110.9=u166.6 U=0.66 Not sure if I did it right.

Sorry! I'm not sure how to find the Fnet.

Physics coefficient of friction question! A 17kg box is being pushed by a 150N force. If the box is accelerating at 2.3m/s2. What is the coefficient of friction on the ground?FNet=μFn Fn= 9.8x17= 166.6N How can I find the fnet?