Physics coefficient of friction question

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Homework Help Overview

The discussion revolves around a physics problem involving the coefficient of friction for a box being pushed with a specific force and experiencing acceleration. The original poster presents a scenario with a 17kg box, a 150N pushing force, and an acceleration of 2.3m/s², seeking to determine the coefficient of friction.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore how to calculate the net force acting on the box and question the method for determining the coefficient of friction. There are discussions about drawing free body diagrams and clarifying the steps involved in the calculations.

Discussion Status

Some participants have offered guidance on clarifying the problem and suggested drawing diagrams. The original poster has shared their calculations, and while there is some validation of the results, the conversation reflects a mix of attempts and confirmations without a clear consensus on the correctness of the approach.

Contextual Notes

There are indications of uncertainty regarding the calculation of net force and the application of the coefficient of friction formula. The original poster expresses confusion about their calculations, and there are references to external resources for learning basic physics concepts.

Jasmin99
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Physics coefficient of friction question!

A 17kg box is being pushed by a 150N force. If the box is accelerating at 2.3m/s2. What is the coefficient of friction on the ground?FNet=μFn
Fn= 9.8x17= 166.6N
How can I find the fnet?
 
Last edited:
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Hi Jasmin99. Welcome to PF.

You should read the how to ask for help forum. Will you specify where you are having problem?.
 
Sorry! I'm not sure how to find the Fnet.
 
Okay. Can you draw the FBD of the object?
 
Here is my work:
Fnet= 150-(17)(2.3)
Fnet= 110.9N
Fnet=uFn
110.9=u166.6
U=0.66
Not sure if I did it right.
 
The answer looks correct
 
Thanks for the help everyone! I have figured it out now.
 
Jasmin99 said:
Here is my work:
Fnet= 150-(17)(2.3)
Fnet= 110.9N
Fnet=uFn
110.9=u166.6
U=0.66
Not sure if I did it right.

Yup, you've got it right. Make sure you post your attempt at the time of asking the question itself.
 

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