Recent content by Jay121

Found a trickier one =\ We colour the vertices of a regular hexagon with two different colours. We do not distinguish colourings if they can be obtained from each other by rotations or reflections. Use Burnside's Lemma to count the colourings. So |G|=2^6=64 Any help on how I go about...

Do you mean |X/G|=\frac{1}{6}(3^3+3.3^2+2.3) As there are 3 reflections? Thanks for this its helped a lot :)

Struggling to apply Burnside's Lemma to an example for the Dihedral group (3) i.e We colour the vertices of an equilateral triangle with three colours: red, blue, green. We do not distinguish colourings if they can be obtained from each other by rotations or reflections. Use Burnside’s...