Recent content by JayaSuria

@Doc Al owh thanks doc. Is this the solution? (b) 1/2 * 6 * 2^2 (c) 1/2 * 6 * 2^2 (d) initial 48J, after 12J. Metal ball lost 36J (e) initial 0J, after 12J. Clay ball gained 12J

@Doc Al , that's the hiccup. For inelastic collision, after the hit, how to calculate for separate objects as before collision? In that case, is the value in (b) same as (c)?

@Doc Al == KE = 1/2mv^2. (a) KE = 1/2 * 6 * 4^2 , equals to 48J

A 6.0kg metal ball moving at 4.0m/s hits a 6.0kg clay ball at rest and sticks to it. The two move at 2.0m/s. a. calculate the kinetic energy of the metal ball before it hits the clay ball. b. calculate the kinetic energy of the metal ball after it hits the clay ball. c. calculate the kinetic...