Recent content by jayz618

  1. J

    Calculating Time Constants for RC and RL Circuits | Simple Physics Homework Help

    Cool, so I was correct on both attempts ? Good News Thanks
  2. J

    Calculating Time Constants for RC and RL Circuits | Simple Physics Homework Help

    For the first one, it doesn't matter that the second resistor comes after the capacitor ?
  3. J

    Calculating Time Constants for RC and RL Circuits | Simple Physics Homework Help

    Homework Statement Calculate the time constants of the following circuits I drew them in the attachment Homework Equations t=RC in a RC Circuit t= L/R in a RL Circuit The Attempt at a Solution Im not sure if in the first one, I would simply add the two...
  4. J

    Solving Spherical Conductor Homework: E, q, r2, C, ε₀

    The problem is, that it is a take home test and he said we were allowed to use any external source we want. I emailed another person in my class to see if he is having the same problem.
  5. J

    Solving Spherical Conductor Homework: E, q, r2, C, ε₀

    No, there is no diagram along with it. It reads exactly how I wrote the original question.
  6. J

    Solving Spherical Conductor Homework: E, q, r2, C, ε₀

    Ok, so I converted 180 Volts/in and came out with 7086.61 Volt/meter. 7086.61 = 8.99x109 ( q / r2) ? Do I know what q is ? I think I've confused myself.
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    Solving Spherical Conductor Homework: E, q, r2, C, ε₀

    I wrote the question exactly as it reads. I don't understand what I can really do only given one known value.
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    Solving Spherical Conductor Homework: E, q, r2, C, ε₀

    Homework Statement A Spherical conductor has an Electric field near its surface of 180 volts per inch. How much charge (in Coulombs) is on the sphere ? How many excess electrons are on the sphere? Will the air around the sphere break down and produce an arc ? Homework Equations Well, I...
  9. J

    Coulombs Law of two metal balls

    So as time passes, the system will move towards ball b's bulkhead ?
  10. J

    Coulombs Law of two metal balls

    I was extremely happy when I read what you just wrote again. Since the distance between both bulkeads is 1.66m on both sides !, that means the object is centered inside the bulkheads, meaning that the charges on each side are equal, causing them to stay the same distance apart on each side...
  11. J

    Coulombs Law of two metal balls

    I really don't know. I just sat down with a tutor at school for 45 minutes and he couldn't explain any of my homework problems, so quite honestly, I give up. You can close this thread if you would like.
  12. J

    Coulombs Law of two metal balls

    I think I see where you are going, because opposites attract, the forces on each bulkhead are the same, which is pulling each ball towards the bulkheads. Meaning the forces on the ball are like forces ? I don't know if I am confusing myself more.
  13. J

    Coulombs Law of two metal balls

    Well, because the string is under tension and is non conducting, wouldn't there have to be a net force acting upon it ? Its what is pushing the balls apart to begin with right ?