jbriggs444's latest activity

*sigh*. Now I will need to watch the video to see what it is actually claiming... Having watched the beginning of the video, I see that...

Right The second part here is correct. That means that the fluid pressure at the air-water interface is sure to be one atmosphere. The...

Yes. Have you considered applying Boyle's law?

Why should it? Are there any specific confounding concerns that you have in mind?

Here's one way to look at it... For a given material, there is a unique maximum value of strain, ##\epsilon_{max}##, at which fracture...

The given answer does not require exact linearity.

Given a set of all sets, one can define the set of all sets not containing themselves. Then you ask yourself, does this set contain...

Only in the limiting case where ##m_1## is zero. In other words, you have an ideal pulley and you hang two objects such that the mass...

If you put the value of the tension ##2T = \dfrac{4m_1m_2}{m_1+m_2}g## and subtract it from the force due to gravity ##(m_1+m_2)g##, it...

Right. That external agent is, of course, the tension in the rope. Right. The center of mass of the two masses is accelerating...

Accelerating upward at 1g is different from freely falling downward at 1g. One requires an external force. The other does not.

Right. That was a braino in my original. Corrected now. Apparently you read it before I fixed it. If you go up with an acceleration of...

In that situation, mass ##m_2## is approximately freely falling while mass ##m_1## is approximately accelerating upward at ##g##. Of...

That is not a substantive response. Since you are not interested in a genuine discussion, I am out. Unattributed straw men devoid of...

You are invoking the formula for centripetal acceleration, ##a = \frac{v^2}{r}##, I suppose. That formula does not apply to rotation...