source of question: https://www.tes.com/teaching-resource/vectors-harder-gcse-practice-questions-for-edexcel-1ma1-syllabus-12621082
Found this vector question by a google search, apparently a person has made this question and it seems almost impossible to solve it without using geometry. Even...
A question states that a ball with a mass of 5 kg and a velocity of 10 m/s collides with a stationary wall. The question then asks for the momentum of the ball after the collision. No other information is given. This is a rather ambiguous question, as it doesn't provide the time taken for the...
This makes the most sense to me. The way i perceive this root (-x)^2 is the same as (-1*x)^2 and so when squaring the negative 1 it becomes positive and that just makes the equation root x^2 and so the root of a (-x) squared number is always. Is this right?
Just to clear up (i think this is where my confusion arises from), the square root of a number (negative or positive) is always the absolute value of the number?
I have a very basic confusion that supports some basic elements of algebra. Being a high school student my teacher couldn't answer this, hope someone could help here.
We know this equation is true: (-x)^2=x^2
but once we square root both sides it becomes this: -x=x
we can see this equation was...
i like this explanation, this is what I am saying, here @jack action has put an approximate sign of 0 and not completely equal. All I am saying is even though the mass of the smaller object may have a very very very small effect on the earth it still is present. I think I am done with this...
two factors affect the fall of the object the distance between the centers and the mass of both objects involved. we can agree that increasing the distance away from the center must influence the rate of "fall" and so likewise increasing or decreasing mass should also affect the rate of fall.
don't overcomplicate everything all I want to know is if this is true. because I have now concluded that however small the mass maybe it still has its own gravity and so must influence its fall toward the earth.