Recent content by jerry fan

Can you explain why there needs to be a negative sign there?

in #6 what is wrong with dV1/dt=I1/C1? i solved the equations by hand and got I1=((R2 - RL)*V1 + RL*V2) / (R2 RL) and I2= (-V1+V2)/R2 At this point I cannot substitute I1 and I2 into the equation dV/dt=I/C?

Yes, that exactly what I had in mind. Thanks for the confirmation. I havn't had to use circuits in a while so I am pretty rusty. I can solve by hand but i have to use them later so i decided that might as well get mathematica to solve for me.

oh my bad i meant R2. I dindt label I because its could be labeled IRL or I2

If C1 is absent, then V2=I*(R2+RL). Then dV2/dt=V2/(C2*(R2+RL))is that correct?

Let V1 be the voltage across C1 and V2 be the voltage across C2. I want to solve for V1 and V2 as a function of time. My idea was to use dV1/dt=I1/C1 and dV2/dt=I2/C2. Then using circuit rules i can express I1 and I2 as functions of V1 and V2 and substitute them into the previous diff eqs...