Recent content by jerryez

If F is the force of air resistance on an object with mass m moving at a constant velocity, which of the following best describes the acceleration of the object when the force of air resistance is reduced by a factor of 4? F=ma It says the answer is equal to (3/4)F/m = a Can...

So if downward Force = mg = 100N ma=mg=F-mg (10kg)(9.81m/s2) = F - (10kg)(9.81m/s2) F = (98.1)+(98.1) F = approximately 200N So the upward force is twice as great as the downward force this makes the downward mass fall at g? Can someone explain the theory behind this?

That makes sense, but the answer in my book says the upward force is equal to 200N. This is what is throwing me off. Maybe the book is wrong. I really appreciate your help rock.freak667 Can you make any sense of the 200N answer? Thanks again Jerry Zink

Then wouldn't that implicate that the mass is not moving?

So if the upward force is equal to the downward force W=U Fw = (10kg)(9.81m/s2) W = 100N U = 100N This doesn't seem right?

?? So if the resultant force is zero how do we find the upward force?

Is the resultant force still the force of the mass 100N downwards?

so W = ma + u a = 9.81m/s2 so W is equal to the downward force of 100N? So this means u = W - ma U = 100N - (10kg)(9.81m/s2) U = 1.9N Is this right? Are you sure its not this "ma = U-W" This would make more sense because then U is = to around 200N

OH! So the resultant force is in the downward direction.

The resultant force should be in the upward direction

Would the upward force be : F=m2a ? F=(10kg)(2)(9.81m/s2) = 196N is this correct?

The two forces are 1. gravitational force on the 10kg mass "going down" 2. The upward force "going up" So the upward force must go against the force of gravity plus the force of the mass. The mass has a force of F=ma = 100N downward Since the upward force is in the opposite...

A 10 kg mass is in free fall with no air resistance. In order to slow the mass at a rate equal to the magnitude of g, an upward force must be applied with magnitude: F=ma F=(10kg)(9.81m/s2) = approximately 100N So in order to slow the mass at a rate equal to g it should be a...

Homework Statement A bottle rocket is launched in the air. The black powder, which propels it, burns leaving an exhaust trail mainly consisting of CO2 gas. If the force propelling the rocket is constant, the rate of change in its velocity INCREASES. Can someone please explain why the change...

Thank you everyone for your help! The answer to the problem is 8 I just didnt understand how they got it. I also see now how the ratio between g and g*sintheta also results in the correct answer. 9.81/1.23 = 7.9