Recent content by jezejeze

yeah ||Q2Q1|| = sqrt {32+12+(-4)2 } = sqrt{26} so the unit vector is: 3/sqrt{26} = 0.588i 1/sqrt{26} = 0.196j -4/sqrt{26}= -0.784k I just misinterpreted the meaning of the '' | '' in the formula as being absolute values instead of the '' || '' of being the ''norme'', or magnitude...

well after a while of trying with the formula stated by RGV in an earlier post, and still not coming to the correct answer.. ( I guess I was doing something wrong.. with a P&P formula..!).. I found a much more logical way! Just need to use the distance between q1 and q2 which is sqrt{26}, use...

So all I need to do is plug in the numbers in the formula .. and that's it ?! No angles and vector stuff... ! Thanks alot!

Homework Statement A charge q1 = 5uC is placed at (x,y,z):(1,2,-1). A charge q2 = -2uC is placed at (x2,y2,z2):(-2,1,3). Determine the electric force (vectorized form) exerted on q1. Homework Equations F12= kQ1Q2 / r2 The Attempt at a Solution At first I tried finding the distance between...