Recent content by jhan

If we noticed, when we released wind from our mouth with a constant velocity ,Why is the speed of the close part of our mouth is maximum speed and while gradually moving away is also gradually weakened until it is zero? How it can be resolved using in mathematical expression?

Fd=.6162N Area=24m^2 Fluid=1027kg/m^3 Cd=? √V=? (Fd .6162N)= (Cd=?)×(pf=1027kg/m^3)×(V^2=?)×(A=24m)÷2 remember Cd is unknown, V is unknown what i did is (Cd)= √(Fd×2)÷(A)÷(pf)×8 √(.6162N×2)÷(24m^2)÷(1027kg/m^3)×8 equals to .02 so i think this is the Cd Then V=...

what i mean.. is if the given is drag force, area, and fluid density,, then 8 is the ratio to find the Cd and velocity.. means (your Drag force is .6162N ) (your area is 24m^2) (then fluid density is 1027kg/m^3) then to find the drag coefficient and velocity is used to 8 ratio,,

Guys,, please check my own way to get Drag coefficient and Terminal Velocity by given Drag force,.. okay,, lets for example: we know drag force is Fd= Cd*pf*v^2*A/2,, ill give little example (Cd=.02)*(pf=1027kg/m^3)*(v^2=.0025m/s)*(A=24m)/2 =( Fd .6162N) so drag force is .6162N,, okay..according...