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Guys,, please check my own way to get Drag coefficient and Terminal Velocity by given Drag force,.. okay,,

lets for example: we know drag force is Fd= Cd*pf*v^2*A/2,, ill give little example (Cd=.02)*(pf=1027kg/m^3)*(v^2=.0025m/s)*(A=24m)/2 =( Fd .6162N) so drag force is .6162N,, okay..according to my analysis drag coefficient and terminal velocity are have constant ratio.. where???how??

okay,, lets do a recheck a given example above,, (.6162Nx2 = 1.2324N) next (1.2334N divide 24m of A= .05135) next (.05135 divide 1027 of fluid density= .00005)next ( .00005* of my own ratio 8= .0004)next (square root of .0004 is = .02 this your drag coefficient) next back to .05135 divide 1027 = .00005) next ( .00005 divide drag coefficient .02 = .0025) next ( square root of .0025 = .05 m/s so this your terminal velocity) :)

lets for example: we know drag force is Fd= Cd*pf*v^2*A/2,, ill give little example (Cd=.02)*(pf=1027kg/m^3)*(v^2=.0025m/s)*(A=24m)/2 =( Fd .6162N) so drag force is .6162N,, okay..according to my analysis drag coefficient and terminal velocity are have constant ratio.. where???how??

okay,, lets do a recheck a given example above,, (.6162Nx2 = 1.2324N) next (1.2334N divide 24m of A= .05135) next (.05135 divide 1027 of fluid density= .00005)next ( .00005* of my own ratio 8= .0004)next (square root of .0004 is = .02 this your drag coefficient) next back to .05135 divide 1027 = .00005) next ( .00005 divide drag coefficient .02 = .0025) next ( square root of .0025 = .05 m/s so this your terminal velocity) :)

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