Recent content by jhess12

thank you so much, I am sorry i didnt get it before, now that you explain it, it seems so simple like i thought, i just don't know why i didnt get it before. sorry dick.

i got it earlier from your earlier post, thanks so much

sorry don't bother

thanks mitleid and dynamicsolo, this helped me out a lot

are du/dy=0 and du/dx=0 because they are perpendicular to the electric field? but i think i understand some. and since i am trying to find F_x right? then i would evaluate W=\intpEsin\theta-find the derivative and i would have my answer right? i worked it out except for the p part of the...

ok well, i figured that if Q4 is 89.5uC, then Q4=Q, then V3=Q/C=89.5/8.5=10.53V. if V3C=Q, then 10.5(6uF)=63.2uC=Q3. this appears to be correct, even though i don't understand why. as for Q1 and Q2, i am still confused, i asked my professor to explain it, but he says i should know how to...

im sorry, i just don't understand, i see all these equation for W(work)=U and i can see that there should be some way for me to solve this problem because as you have explained it to me, it actually seems very simple, except that i don't know how to put the gradient into the equation. i know...

i just don't know. i think that it might be E=\deltaV/\deltax

so F=-U, so F=pEcos\theta, and (dE/dx) is the direction of the electric field as it changes with the coordinate x because the electric field is nonuniform right?

Homework Statement http://books.google.com/books?id=1DZz341Pp50C&pg=PA678&dq=serway+four+capacitors+are+connected&sig=iwUiJRqZDNHDGOfQfHHvh_9aQ3Y problem 41 on this link. I got the equivalent capacitance for part a. for the two capacitors with 15 and 3uF- C_{eq}=2.5uF for capacitor...

Homework Statement A small object with electrc dipole moment \overrightharpoonup{p} is placed in a nonuniform electric field \overrightarrow{E} =E(x)\hat{i}. That is, the field is in the x direction and its magnitude depends on the coordinate x. Let \theta represent the angle between the...