Recent content by jimbit
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Calc II - Alternating Series Test/Limits
Oh, goodness, I understand now, as 2/x becomes increasingly small, it basically becomes 0. e^0 = 1.- jimbit
- Post #6
- Forum: Calculus and Beyond Homework Help
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J
Calc II - Alternating Series Test/Limits
Well, as 2/x becomes infinitely small, e goes to 1. I see that now, after doing some calculations. However, I'm just not sure why it doesn't go to zero instead. I seem to be missing some crucial fact about e..- jimbit
- Post #5
- Forum: Calculus and Beyond Homework Help
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J
Calc II - Alternating Series Test/Limits
f(w) = e^w is continuous. For 2/x, it is not continuous at 0. But it is continuous from 1 to infinity. So, the limit is 1?- jimbit
- Post #3
- Forum: Calculus and Beyond Homework Help
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J
Calc II - Alternating Series Test/Limits
Hello PF, I've got a homework question I'm having some trouble with regarding series, particularily alternating series. The question asks you to test the series for convergence or divergence for an alternate series by using the A.S.T. : [SIZE="1"]∞ [SIZE="4"]∑ (-1)n-1e2/n...- jimbit
- Thread
- Alternating series Series
- Replies: 5
- Forum: Calculus and Beyond Homework Help