Recent content by jitu16

Which boundary condition are you referring to?? If it's periodic then your calculation is right but if it's anti-periodic then your calculation is wrong.

Entropy is a function of T,V or T,P. If you still can't recall, S=-\frac{\partial G(T,V)}{\partial T} and, S=-\frac{\partial A(T,P)}{\partial T}

Are you referring to eqn 13?? If that's the case here's explanation: \frac{\partial U(S,V)}{\partial V}= \frac{\partial U}{\partial S} \frac{\partial S}{\partial V}+\frac{\partial U}{\partial V} \frac{\partial V}{\partial V} =\frac{\partial U}{\partial S} \frac{\partial S}{\partial...

I know physics, I graduated from physics. Currently doing masters in Theoretical Physics. But on the other hand my knowledge of biology is next to zero. How should I proceed? A suggested list of book with ordering will be helpful.

Yes we demand it, if it's not the case it's not much of a physics anymore. But even if law of physics changes(energy not conserved anymore) it changes slowly. The apple has not gone to heaven as far as civilization can remember :p

Did you understood the transfer matrix technique? the first n-1 spin sum just becomes the normal trace of the transfer matrix. But then you have \sigma_m, but the possible value of \sigma_m are 1 and -1, with introduction of pauli matrix(+1 and -1 remember?), it just becomes a normal trace once...

You don't assume that |\psi>=\alpha |1>+ \beta |2>, there is a reason for that. The completeness relation gives, I=|1><1|+|2><2| [look up completeness relation if you don't know about it.] which means, |\psi>=I|\psi>=|1><1|\psi>+|2><2|\psi> or, |\psi>=\alpha |1>+ \beta |2> , where...

Hello I am Jitu, currently doing masters in theoretical physics. Current interest is QGP. Hope to get to know you people. :)