Hello,
In my study i came across to solve the analytical solution for coupled equation y(x,t) and z(x,t).The equations contains" f " function which is a function of the first variable exponentially.
The first equation is : ∂y/∂t=∂^2(y)/∂x^2- 2*f(y)*z;
The second equation ...
Thankyou for the reply. However in your explanation you have said d^2y/dt^2= dz/dt= (dz/dy)(dy/dt)= z dz/dy.if i understood it correctly,the equation becomes z*dz/dy- z= e^y, not " dz/dy- z= e^y,". hence it will not be linear first order equation.
Thank you in advance.
Hello,
I tried to find the non linear second order differential solution of:
diff(y(t), t, t)-(diff(y(t), t))+exp(y(t)) = 0
can anyone please help me?
Kind regards,
JJ