Non linear second order differential equation

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SUMMARY

The discussion focuses on solving the non-linear second-order differential equation represented as diff(y(t), t, t) - diff(y(t), t) + exp(y(t)) = 0. Participants clarify that diff(y(t), t, t) and diff(y(t), t) denote the second and first derivatives, respectively. The transformation to a first-order linear equation is debated, with the correct formulation being z * dz/dy - z = e^y, which indicates a misunderstanding of the linearization process. The conversation emphasizes the importance of accurately applying derivative transformations in differential equations.

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jj231
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Hello,
I tried to find the non linear second order differential solution of:
diff(y(t), t, t)-(diff(y(t), t))+exp(y(t)) = 0
can anyone please help me?

Kind regards,
JJ
 
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What do "diff(y(t), t, t)" and "diff(y(t), t)" mean? Second and first derivatives? I would think the usual "d^2y/dt^2" and "dy/dt" would be simpler. If this is y''- y'= e^y then, since the independent variable, t, does not appear explicitely, we can use "quadrature". Let z= dy/dt so that d^2y/dt^2= dz/dt= (dz/dy)(dy/dt)= z dz/dy. Then the equation becomes dz/dy- z= e^y, a linear first order differential equation. Solve for z as a function of y then solve dy/dt= z for y as a funtion of t.
 
Thankyou for the reply. However in your explanation you have said d^2y/dt^2= dz/dt= (dz/dy)(dy/dt)= z dz/dy.if i understood it correctly,the equation becomes z*dz/dy- z= e^y, not " dz/dy- z= e^y,". hence it will not be linear first order equation.

Thank you in advance.
 

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