Recent content by jketts

\int_{v}^{1-v} I think I had that part wrong.

Sure, \int\int_{D}{} \frac{1}{1+xy} dxdy D={(x,y);0≤x≤1,0≤y≤1}, x=u-v, y=u+v. That's all I am given.

The original problem wants to change it from x and y to terms of u and v. I.e., x=u-v, y=u+v.

Hey everyone, I need to do the following integral. I just need a little help getting this started, I'm not sure where I need to go. Here is the problem: \int_{0}^{1-v} du \int_{0}^{\frac{1}{2}} dv \frac{1}{1+u^2-v^2} I think I have the boundaries for the integral set up correctly, {0≤v≤1/2...