Recent content by jkr

Hi again, If \rho \bar{u'v'} =0 at y = \pm H then the model \rho \bar{u'v'}=\frac{by}{c+dy^2} doesn't work because b=0. However, for the case \rho \bar{u'v'} =\frac{by+ey^3}{c+dy^2}, How does it work? []s

Tks a lot for this! =D

Homework Statement Hello! I need some help with a problem: Problem: Turbulent flow beteween parallel flat plates. It is defined: [ tex ] \tau = \mu \frac{d\bar{u}}{dy}-\rho\bar{u'v'} [ \tex ] The exercise gives that [ tex ] \tau = a y [ \tex ] and [ tex ] \rho\bar{u'v'} =...