Constants definition - turbulent vel. profile

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jkr
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Homework Statement



Hello!

I need some help with a problem:

Problem: Turbulent flow beteween parallel flat plates.

It is defined:

[ tex ] \tau = \mu \frac{d\bar{u}}{dy}-\rho\bar{u'v'} [ \tex ]

The exercise gives that [ tex ] \tau = a y [ \tex ] and [ tex ] \rho\bar{u'v'} = \frac{by}{c+dy^2} [ \tex ], where [ tex ] a,b,c,d[ \tex ] are constants.

I need to know: How can I choose these constants? I'm looking for an approximate solution.

Until now, I used just the no-slip condition at [ tex ] \pm H [ \tex ] and [ tex ] \frac{du(y=0)}{dy}=0 [ \tex ]

Tks for the help!

Homework Equations


[ tex ] \tau = \mu \frac{d\bar{u}}{dy}-\rho\bar{u'v'} [ \tex ]
[ tex ] \tau = a y [ \tex ]
[ tex ] \rho\bar{u'v'} = \frac{by}{c+dy^2} [ \tex ]

The Attempt at a Solution



 
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jkr said:
Hello!

I need some help with a problem:

Problem: Turbulent flow beteween parallel flat plates.

It is defined:

[tex]\tau = \mu \frac{d\bar{u}}{dy}-\rho\bar{u'v'}[/tex]

The exercise gives that [tex]\tau = a y[/tex] and [tex]\rho\bar{u'v'} = \frac{by}{c+dy^2}[/tex], where [tex]a,b,c,d[/tex] are constants.

I need to know: How can I choose these constants? I'm looking for an approximate solution.

Until now, I used just the no-slip condition at [tex]\pm H[/tex] and [tex]\frac{du(y=0)}{dy}=0[/tex]

Tks for the help!

Homework Equations


[tex]\tau = \mu \frac{d\bar{u}}{dy}-\rho\bar{u'v'}[/tex]
[tex]\tau = a y[/tex]
[tex]\rho\bar{u'v'} = \frac{by}{c+dy^2}[/tex]
Hi jkr! http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif

I'm astonished that you posted your question with its non-functioning itex formatting instructions. I have fixed them for you. Don't include unnecessary spaces inside the [...] instruction. And its [/tex] NOT [\tex].

I can't help you with a fluidics question, but now maybe someone else can. :smile:
 
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Hi again,

If [tex]\rho \bar{u'v'} =0[/tex] at [tex]y = \pm H[/tex] then the model [tex]\rho \bar{u'v'}=\frac{by}{c+dy^2}[/tex] doesn't work because [tex]b=0.[/tex]
However, for the case
[tex]\rho \bar{u'v'} =\frac{by+ey^3}{c+dy^2},[/tex] How does it work?

[]s